2p^2-9p-126=0

Solution for 2p^2-9p-126=0 equation:

2p^2-9p-126=0

a = 2; b = -9; c = -126;
Δ = b2-4ac
Δ = -92-4·2·(-126)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-33}{2*2}=\frac{-24}{4}
=-6
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+33}{2*2}=\frac{42}{4}
=10+1/2
$